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recursionMystery4

Language/Type: JavaScript recursion mystery
Author: Melissa Hovik (on 2016/09/25)

For each call to the following function, indicate what value is returned:

function mystery4(x, y) {
    if (x < 10 || y < 10) {
        return x + y;
    } else if (x > y) {
        let a = mystery4(parseInt(x / 2), parseInt(y / 2));
        let b = mystery4(y, x - y);
        return a + b;
    } else {
        return mystery4(x, parseInt(y / 2));
    }
}
mystery4(10, 18);
mystery4(6, 15);
mystery4(24, 10);
mystery4(26, 12);
mystery4(19, 20);

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